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Old 08-01-2003, 02:42 PM   #1
QuikSand
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OT - Number game/puzzle for Fridayidle minds

We've done stuff like this before - since so many people seem to be clock-watching, let's try another round. And we'll make this a little more complicated.

Your goal: use the assigned set of numbers, along with any combination of arithmetic operations, to get to a total as close as possible to the target number(s).

For each set, you must use all these numbers:

6, 7, 19, 21, and 57

You may use these functions:

+, -, x, / = obvious
parentheses or brackets as needed

You may not just press numbers together into one larger numeral (e.g. 6 and 7 into 67)

You may not use exponents (too easy to compress something to zero that way)

You may not use factorials


Let's see... for the puzzle, let's set the target number at 50 to start with. If anyone hits that on the nose, then we'll let that person set a new target number, and we'll go from there. Or, if we agree that we can't hit a number on the button - we'll go with the closest we could find, and that person sets the next target.

50 it is.


(edit - disallow exponents, and factorials)


Last edited by QuikSand : 08-01-2003 at 02:55 PM.
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Old 08-01-2003, 02:45 PM   #2
QuikSand
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Hmmm...

57 - (21/6) - (19/7) = ~50.79

We can probably do better...
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Old 08-01-2003, 02:45 PM   #3
Franklinnoble
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Are you a math teacher or something?
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Old 08-01-2003, 02:47 PM   #4
QuikSand
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Something.
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Old 08-01-2003, 02:47 PM   #5
QuikSand
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...or didn't I understand the question properly?
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Old 08-01-2003, 02:47 PM   #6
Celeval
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Just to set a target:

(57+21+19) - (7*6) = 55


Nevermind, forgot QuickSand was MathGod.

Last edited by Celeval : 08-01-2003 at 02:49 PM.
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Old 08-01-2003, 02:50 PM   #7
QuikSand
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This gets us pretty darned close... but also exposes a potential weakness in the game.

(57-7)+(6/(19^21))

This rounds to 50 in Excel... maybe we need to drop the ability to use powers?

EDITED above - no exponents.

Last edited by QuikSand : 08-01-2003 at 02:53 PM.
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Old 08-01-2003, 02:51 PM   #8
QuikSand
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Quote:
Originally posted by Celeval
Nevermind, forgot QuickSand (sic) was MathGod.

Naw, just got a head start.

Last edited by QuikSand : 08-01-2003 at 02:53 PM.
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Old 08-01-2003, 02:51 PM   #9
panerd
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6/19/21 + 57 - 7 = 50.015...
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Old 08-01-2003, 02:53 PM   #10
dacman
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57 - (7!/6!) + (19^-21) = ~50.0000000000000000000000000001

Yeah, exponents make it too easy.
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Last edited by dacman : 08-01-2003 at 02:54 PM.
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Old 08-01-2003, 02:54 PM   #11
QuikSand
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Hmmmm... maybe we'll need to dump the factorials also... also make it too easy to use fewer of the terms.

Sorry - seems to be a work in progress.
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Old 08-01-2003, 02:55 PM   #12
QuikSand
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Anyone else ready to concede to panerd on 50?
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Old 08-01-2003, 02:57 PM   #13
panerd
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57/19 x 21 - 7 - 6 = 50 exactly
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Old 08-01-2003, 02:58 PM   #14
QuikSand
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Nicely done. Pick the next target number.
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Old 08-01-2003, 02:58 PM   #15
dacman
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No reason you couldn't do something like:

6/19!/21! + 57 - 7 = ~ 50 + 1*10^-9999999999999999999999
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Old 08-01-2003, 02:58 PM   #16
panerd
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Same numbers, different target or new numbers?
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Old 08-01-2003, 02:59 PM   #17
QuikSand
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Quote:
Originally posted by panerd
Same numbers, different target or new numbers?

Same numbers, different target - for now, at least.

(The 57/19 = 3 is unfortunate, I think)
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Old 08-01-2003, 03:00 PM   #18
dacman
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My rule when I ran something similar is that the answer must be an integer -- it prevents a lot of the silliness above.
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Old 08-01-2003, 03:00 PM   #19
panerd
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Allright, lets go with 100 as the target.
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Old 08-01-2003, 03:03 PM   #20
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7 x 6 + 57 + 21 - 19 = 101
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Old 08-01-2003, 03:05 PM   #21
QuikSand
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57+(7*6)+(21/19) = 100.1053
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Old 08-01-2003, 03:06 PM   #22
Franklinnoble
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I have to stop reading this thread... I feel like Forrest Gump in a room full of Einsteins.
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Old 08-01-2003, 03:08 PM   #23
QuikSand
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Anyone beating that 100.1053 ?
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Old 08-01-2003, 03:08 PM   #24
panerd
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Quote:
Originally posted by QuikSand
57+(7*6)+(21/19) = 100.1053

If you switch the 21/19 to 19/21 you get just a little bit closer. There has got to be a way to get exactly 100 using 10^2 somehow.
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Old 08-01-2003, 03:11 PM   #25
QuikSand
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Good catch, panerd:

57+(6*7)+(19/21) = ~99.90476
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Old 08-01-2003, 03:11 PM   #26
lurker
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6 x 7 + 57 + 7 - 6 = 100
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Old 08-01-2003, 03:14 PM   #27
QuikSand
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Quote:
Originally posted by lurker
6 x 7 + 57 + 7 - 6 = 100

A couple too many each of 6 and 7, not enough of 19 and 21.
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Old 08-01-2003, 03:14 PM   #28
QuikSand
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Well... I'll set the new target, and we'll go from there.

If anyone can hit 100 on the nose - they're welcome to keep working on it. Prize is ... uh... they get to pick a new set of five numbers to work with in bulding.



For now:

Use 6,7,19,21 and 57 to make... 88.
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Old 08-01-2003, 03:15 PM   #29
lurker
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Whoops, sorry, I knew I didn't read the rules well enough!
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Old 08-01-2003, 03:17 PM   #30
digamma
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(21-7)*6+(57/19)=87
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Old 08-01-2003, 03:17 PM   #31
Radii
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57+21+7+(19/6) = ~88.16667
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Old 08-01-2003, 03:18 PM   #32
QuikSand
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Radii beat me to mine... best I've got so far.
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Old 08-01-2003, 03:19 PM   #33
digamma
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(19-6)*7+(57/21)=88.2857

Last edited by digamma : 08-01-2003 at 03:20 PM.
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Old 08-01-2003, 03:22 PM   #34
QuikSand
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Weird one:

57+(21*19)/(7+6) = ~87.69231

...not a winner, but strangely close.
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Old 08-01-2003, 03:24 PM   #35
QuikSand
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Maybe we should put a time limit on each set? Ten minutes (marked by the board timer) and we move on?
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Old 08-01-2003, 03:25 PM   #36
digamma
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Time limit would be good.
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Old 08-01-2003, 03:26 PM   #37
QuikSand
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Okay - Radii, you're on for the next target number.

Ten minutes apiece from here on out. I'm good for about three more, as I watch the clock...

Last edited by QuikSand : 08-01-2003 at 03:27 PM.
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Old 08-01-2003, 03:29 PM   #38
QuikSand
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Okay, Radii has drifted to the dynasty section.

Here's our new target number: 600
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Old 08-01-2003, 03:32 PM   #39
QuikSand
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(57*(19-6))-(21*7) = 594

Doubtful that's a winner, but it's something.
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Old 08-01-2003, 03:32 PM   #40
panerd
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(21 + 19) x (7 + 6) + 57 = 577

Last edited by panerd : 08-01-2003 at 03:33 PM.
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Old 08-01-2003, 03:39 PM   #41
QuikSand
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(57*6)+(21*(19-7)) = 594
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Old 08-01-2003, 03:39 PM   #42
Masked
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(57-7)*6*(21-19) = 600
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Old 08-01-2003, 03:40 PM   #43
QuikSand
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Quote:
Originally posted by Masked
(57-7)*6*(21-19) = 600

Good heavens that was easy.

You're up.
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Old 08-01-2003, 03:40 PM   #44
VPI97
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(6 + 7 + 19 - 21) * 57 = 627

Edit - Yeah, 627 was close...

Last edited by VPI97 : 08-01-2003 at 03:41 PM.
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Old 08-01-2003, 03:41 PM   #45
Masked
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Same numbers: 6, 7, 19, 21, 57

Target: 257

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Old 08-01-2003, 03:41 PM   #46
panerd
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Here I am trying to find ways to get the other four numbers to equal 28.5 so I can multiply by 21 and there is a way to get exactly 600!
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Old 08-01-2003, 03:44 PM   #47
digamma
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(57-7)*6-(21+19)=260
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Old 08-01-2003, 03:47 PM   #48
panerd
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(6 + (7/21)) ^ (57/19) = 254.03

A little closer than 260.
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Old 08-01-2003, 03:48 PM   #49
Masked
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(19-7)*21+57/6 = 261.5
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Old 08-01-2003, 03:49 PM   #50
Masked
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(19-6)*21-57/7 = 254.8571

better
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